Question

Решите неравенство !! Пожалуйстаа!

Answer 1

$sqrt{4-x^2}cdot log_{0,5}frac{(x+1)^2}{3x+1}leq 0\\ODZ:; ; left { {{4-x^2geq 0} atop {frac{(x+1)^2}{3x+1}>0}} right.; left { {{(4-x)(4+x)geq 0} atop {3x+1>0}} right.; left { {{xin [-4,4, ]} atop {xin (-frac{1}{3},+infty )}} right. ; ; Rightarrow ; ; xin (-frac{1}{3},4, ]\\Tak; kak; ; sqrt{4-x^2}geq 0; ; pri; ; xin ODZ; ; Rightarrow ; ; log_{0,5}frac{(x+1)^2}{3x+1}leq 0; ,\\frac{(x+1)^2}{3x+1}geq 1; ,; ; frac{(x+1)^2}{3x+1}-1geq 0; ,$

$frac{(x+1)^2-3x-1}{3x+1}geq 0; ; ,; ; frac{x^2+2x+1-3x-1}{3x+1}geq 0; ; ,; ; frac{x(x-1)}{3x+1}geq 0; ,\\znaki:; ; ---(-frac{1}{3})+++[, 0, ]---[, 1, ]+++\\xin (-frac{1}{3},0, ]cup [, 1,+infty )\\left { {{xin (-frac{1}{3},0, ]cup [, 1,+infty )} atop {xin (-frac{1}{3},4, ]}} right. ; ; ; Rightarrow ; ; underline {; xin (-frac{1}{3},0, ]cup [, 1,4, ]; }$