Question

Решив систему неравенств:
{-10(×-4)<3(4-2×)-3×,
{1,6(0,1×-3)>3(-6+0,1×)+0,3×

Answer 1

$begin{cases}-10(x-4)<3(4-2x)-3x\1.6(0.1x-3)>3(-6+0.1x)+0.3xend{cases}Rightarrowbegin{cases}-10x+40<12-6x-3x\0.16x-4.8>-18+0.3x+0.3xend{cases}Rightarrow\Rightarrowbegin{cases}-10x+40<12-9x\0.16x-4.8>-18+0.6xend{cases}Rightarrowbegin{cases}10x-9x>40-12\0.6x-0.16x<18-4.8end{cases}Rightarrow\Rightarrowbegin{cases}x>28\0.44x<13.2end{cases}Rightarrowbegin{cases}x>7\x<30end{cases}Rightarrow xin(28;;30)$