Question

помогите пожалуйста очень срочно​

Answer 1

А)

$(x + 6)^{2} = x^{2} + 12x + 36$

Б)

$(3a - 1)^{2} = 9 {a}^{2} - 6a + 1$

В)

$(3y - 2)(3y + 2) = 9 {y}^{2} - 4$

Г)

$(4a + 3k)(4a - 3k) = 16 {a}^{2} - 9 {k}^{2}$

Answer 2

$(x + 6) {}^{2} = x {}^{2} + 2x times 6 + 6 {}^{2} = x {}^{2} + 12x + 36$

$(3a - 1) {}^{2} = (3a) {}^{2} - 2 times 3a times 1 + 1 {}^{2} = 9a {}^{2} - 6a + 1$

$(4a + 3k)(4a - 3k) = (4a) {}^{2} - (3k) {}^{2} = 16a {}^{2} - 9k {}^{2}$

Дальше не знаю