Question

Помогите пожалуйста

Answer 1

tg(pi+t)=tg(t)
sin(6pi+t)=sin(t)
$cos(t ) = sqrt{1 - sin(t) {}^{2} }$
$cos(t) = frac{5}{13}$
$tan(t) = frac{ sin(t) }{ cos(t) }$
$tan(t) = frac{12}{13} div frac{5}{13} = frac{12}{5} = 2.4$

Answer 2

tg(pi+t)=tg(t)
sin(6pi+t)=sin(t)
cos(t ) = sqrt{1 - sin(t) {}^{2} }
cos(t) = frac{5}{13}
tan(t) = frac{ sin(t) }{ cos(t) }
tan(t) = frac{12}{13} div frac{5}{13} = frac{12}{5} = 2.4

Answer 3

tg(pi+t)=tg(t)

sin(6pi+t)=sin(t)

cos(t ) = sqrt{1 - sin(t) {}^{2} }

cos(t) = frac{5}{13}

tan(t) = frac{ sin(t) }{ cos(t) }

tan(t) = frac{12}{13} div frac{5}{13} = frac{12}{5} = 2.4