Question

tga+ctga*sin2a=2 объясните пожалуйста​

Answer 1

$(tgalpha+ctgalpha)sin(2alpha)=(frac{sinalpha}{cosalpha}+frac{cosalpha}{sinalpha})2sinalpha cosalpha=\\2(frac{sinalpha}{cosalpha}cdot sinalpha cosalpha+frac{cosalpha}{sinalpha}cdot sinalpha cosalpha)=2(sin^2alpha+cos^2alpha)=2cdot1=2$