Question

упрости выражение (х-6)^2+(х-3)(х+3)+12х

Answer 1

$(x-6)^2 + (x-3)(x+3) + 12x\ x^2-12x+36+x^2-9+12x\ x^2+36+x^2-9\2x^2+36-9\2x^2+27$

Answer 2

$(x-6)^{2}+(x-3)(x+3)+12x \ \ x^{2}-12x+36+(x-3)(x+3)+12x \ \ x^{2}-12x+36+x^{2}-9+12x=2x^{2}+27$