Question

Реши уравнение:
13x2+39x−(x+3)=0

Корни уравнения
x1=
x2=

Answer 1

$13x {}^{2} { + 39x - }(x + 3) = 0 \ 13x ^{2} + 39x - x - 3 = 0 \ 13 ^{2} + 38x - 3 = 0 \ d = (b ^{2} ) - 4ac = 38 {}^{2} - 4 times 13 times ( - 3) = 1444 + 156 = sqrt{1600} = 40 \ x1 = frac{38 + 40}{2} = frac{78}{2} = 39 \ x2 = frac{ - 2}{2} = - 1$