Question

разложить на множетели b^2- c^2-10 ( b-c)^2​

Answer 1

 =(b-c)(b+c)-10(b-c)^2=(b-c)(b+c-10b+10c)=(b-c)(11c-9b)

Answer 2

$(b - c)(b + c) - 10( {b - c)}^{2} = \ (b - c)(b + c - 10(b - c)) = \ (b - c)(b + c - 10b + 10c) = \ (b - c)(11c - 9b)$