Question

4 - 1 целая 9/16 х во 2 =0​

Answer 1

$4-1frac{9}{16}x^{2}=0\\4-frac{25}{16}x^{2}=0\\2^{2}-(frac{5}{4}x)^{2} =0\\(2-frac{5}{4}x)(2+frac{5}{4}x)=0\\1)2-frac{5}{4} x=0\\frac{5}{4}x=2\\x_{1} =frac{8}{5}=1,6 \\2)2+frac{5}{4}x=0\\frac{5}{4}x=-2\\x_{2} =-frac{8}{5} =-1,6$