Question

Пожалуйста, помогите

Answer 1

Ответ:

Пошаговое объяснение:

1)

$dfrac{32^{n+1}times 9^n}{3^{2n-1}times 2^{5n}}= dfrac{2^{5n+5}times 3^{2n}}{3^{2n-1}times 2^{5n}}=2^{5n+5-5n}times 3^{2n-2n+1}=2^5times3=96$

2)

$dfrac{20^{n+2}}{2^{2n-1}times 5^{n+3}} =dfrac{2^{2n+4}times 5^{n+2}}{2^{2n-1}times 5^{n+3}} =2^{2n+4-2n+1}times 5^{n+2-n-3}=2^5times 5^{-1}=dfrac{32}{5} =6,4$

3)

$dfrac{2x}{3} -dfrac{4x-1}{4} =5-dfrac{2x-7}{24} \\8*2x-6(4x-1)=120-(2x-7)\\16x-24x+6=120-2x+7\\8x-2x=6-127\\6x=-121\\x=-dfrac{121}{6} =-20dfrac{1}{6}$

4)

$4x^3-3x-1=0\\4x^3-4x^2+4x^2-3x-1=0\\4x^2(x-1)+4x(x-1) +4x - 3x - 1= 0\\(x-1)(4x^2+4x+1)=0\\(x-1)(2x+1)^2=0\\x_1=1\\x_{2,3}=-0,5$