Question

Преобразить тригонометрическое выражение:
(cos(a)*tg(a))'2+(sin(a)*ctg(a))'2=?

Answer 1

$( { cosalpha times tg alpha ) }^{2} + ( { sinalpha times ctg alpha ) }^{2} = \ ( {cos alpha times frac{sin alpha }{cos alpha } )}^{2} + ( {sin alpha times frac{cos alpha }{sin alpha } )}^{2} = \ sin {}^{2} alpha + {cos}^{2} alpha = 1$