Question

cd+d^2/6•12/(c+d) при c=1, d=2
(2a/1+a + 1/a):a/1+a=

Answer 1

$frac{cd+d^{2} }{6}$ · $frac{12}{c+d}$

$frac{1·2+[tex]2^{2}$}{6}[/tex]·$frac{12}{1+2}$=$frac{2+4}{6}$·$frac{12}{3}$=$frac{6}{6}$·$frac{12}{3}$=1·$frac{12}{3}$=$frac{12}{3}$=4