Question

Решить уравнение
2cos(1/3x-10pi)=√3

Answer 1

x={π/2+6kπ

{11π/2+6kπ

Answer 2

$2cos(frac13x-10pi)=sqrt3\cos(frac13x-10pi)=frac{sqrt3}2\frac13x-10pi=30^0\frac13x=30^0+10pi\x=3(30^0+10pi)\x=90^0+10pi\xapprox121.415926536^0$