Question

14 корней из 2(sin^4 3п/8*cos^4 3п/8)

Answer 1

$14sqrt{2}(sin^4frac{3pi }{8}-cos^4frac{3pi }{8})=14sqrt{2}(sin^2frac{3pi }{8}-cos^2frac{3pi }{8})(sin^2frac{3pi }{8}+cos^2frac{3pi }{8})=\=14sqrt{2}*(-cosfrac{3pi }{4})=14sqrt{2}*cosfrac{pi }{4}=14sqrt{2}*frac{sqrt{2}}{2}=14$

УДАЧИ ВАМ И УСПЕХОВ)))!!!

Answer 2

$14sqrt{2}(Sin^{4}frac{3pi }{8}-Cos^{4} frac{3pi }{8})=14sqrt{2}(Sin^{2}frac{3pi }{8}+Cos^{2}frac{3pi }{8})(Sin^{2}frac{3pi }{8}-Cos^{2} frac{3pi }{8})=14sqrt{2}*1*(-Cosfrac{3pi }{4})=-14sqrt{2}Cos(pi-frac{pi }{4} )=14sqrt{2}Cosfrac{pi }{4}=14sqrt{2}*frac{1}{sqrt{2} } =14$