Question

Решите пж
Разложить на множители : 4(3a^2+2b)^2 - (3a^2-2b)^2

Answer 1

4(9a⁴+12a²b+4b²)-(9a⁴-12a²b+4b²)=

=36a⁴+48a²b+16b²-9a⁴+12a²b-4b²=

=27a⁴+60a²b+12b²=3(9a⁴+20a²b+4b²)=

=3(9a⁴+18a²b+2a²b+4b²)=

=3(9a²(a²+2b)+2b(a²+2b)=

=3(a²+2b)(9a²+2b)