Question

Найдите корень уравнения  (1/7)^2x-12= 1/49

Answer 1

$(frac17)^{2x-12}=frac1{49}$
$(frac17)^{2x-12}=(frac1{7})^2\ 2x-12=2\2x=2+12\2x=14\x=14:2\x=7$