Question

Решите неравенство$(frac{1}{81} )^{4x-5} geq 27$

Answer 1

$((3^{-4})^{4x-5}geq3^3$

$3^{20-16x}geq 3^3$

20-16x≥3

-16x≥-17

x≤ 17/16

x∈(-∞; 17/16]