Question

ctg450°-sin 5π/4= 0-1 =
(решить)​

Answer 1

$Ctg450^{o}-Sinfrac{5pi }{4}=Ctg(360^{o}+90^{o})-Sin(pi+frac{pi }{4})=Ctg90^{o}+Sinfrac{pi }{4}=0+frac{sqrt{2} }{2}=frac{sqrt{2} }{2}$