Question

Помогите решить, пожалуйста.
$frac{11x-4}{5}=frac{x^{2}}{2}$

Answer 1

$2(11x - 4) = 5x {}^{2}$

$2(11x - 4) - 5x {}^{2} = 0$

$22x - 8 - 5x {}^{2} = 0$

$- 22x + 8 + 5x {}^{2} = 0$

$5x {}^{2} - 2x - 20x + 8 = 0$

$x times (5x - 2) - 4(5x - 2) = 0$

$(5x - 2) times (x - 4) = 0$

$5x - 2 = 0 \ x - 4 = 0$

$x = frac{2}{5} \ x = 4$

Answer 2

$2(11x-4)=5x^2\22x-8=5x^2\5x^2-22x+8=0\D=(-22)^2-4*5*8=484-160=324\x_1=frac{-(-22)+sqrt{324}}{2*5}=frac{22+18}{10}=4\ x_2=frac{-(-22)-sqrt{324}}{2*5}=frac{22-18}{10}=frac{4}{10}=0.4$