Question

Решите уравнение
[х-4] = х^2 - 5х + 4

Answer 1

$x-4=x^2-5x+4\x-4=(x-4)(x-1)\x-4-(x-4)(x-1)=0\(x-4)(1-(x-1))=0\(x-4)(1-x+1)=0\(x-4)(2-x)=0\x_1=4\x_2=2$