Question

Найти производные
Cos(x^2+4x)
Arctg(5x^3+3x)

Answer 1

1) (Cos(x² + 4x))' = - Sin(x² + 4x) * (x² + 4x)' = - (2x + 4)Sin(x² + 4x)

$2)(arctg(5x^{3}+3x))'=frac{1}{1+(5x^{3}+3x)^{2}}*(5x^{3}+3x)'=frac{15x^{2}+3 }{1+(5x^{3}+3x)^{2}}$