Question

x^2+(x+3)*5=39
ДОПОМОЖІТЬ!!!

Answer 1

x^2+(x+3)*5=39

x^2+5x+15-39=0

x^2+5x-24=0

a=1, b=5, c=-24

D=b^2-4ac=25+96=121

$x1 = frac{ - b + sqrt{d} }{2a} = frac{ - 5 - 11}{2} = - frac{16}{2} = - 8$

$x2 = frac{ - b + sqrt{d} }{2a} = frac{ - 5 + 11}{2} = frac{6}{2} = 3$

Ответ: -8; 3

Answer 2

дякую!!!!