Question

arcsin(-1/√2)-arcsin1+arcsin√3/2

Answer 1

-π/4-π/2+π/3

(-3π-6π+4π)/12

-5π/12

Answer 2

arcsin(-1/√2)-arcsin1+arcsin(√3/2)= -arcsin(1/√2)-π/2+π/3= -π/4-π/2+π/3=

=(-3π-6π+4π)/12= -5π/12