Question

Помогите решить
sin x = -0,5 * √2

Answer 1

sinx = -√2/2;

x = (-1)ⁿarcsin(-√2/2) + πn, n∈Z;

x = (-1)ⁿ⁺¹π/4 + πn, n∈Z.

Ответ: (-1)ⁿ⁺¹π/4 + πn, n∈Z.

Answer 2

$sinx=-0,5cdot sqrt2\\x=(-1)^{n}cdot arcsin(-frac{sqrt2}{2})+pi n,; nin Z\\x=(-1)^{n}cdot (-frac{pi}{4})+pi n,; nin Z\\x=(-1)^{n+1}cdot frac{pi}{4}+pi n,; nin Z$