Question

помогите срочно!!!!!!!!!!!!​

Answer 1

$tt cfrac{x-2}{x}= cfrac{3-2}{3}=cfrac{1}{3}\\\ cfrac{(t-7)^2}{2s}=cfrac{(4-7)^2}{2cdot(-1)}=cfrac{(-3)^2}{-2}=cfrac{9}{-2}=-4,5\\\ cfrac{y+6}{y-2}=cfrac{4+6}{4-2}=cfrac{10}{2}=5\\\ cfrac{x-5}{(2y+3)^2}=cfrac{2-5}{(2(-2)+3)^2}=cfrac{-3}{(-4+3)^2}=cfrac{-3}{(-1)^2}=cfrac{-3}{1}=-3$