Question

Решите уровняете пж
1)х^2-х=0
2) 2x^2+4x=0

Answer 1

$x {}^{2} - x = 0 \ \ x times (x - 1) = 0 \ \ x1 = 0 \ x - 1 = 0 \ x2 = 1 \ \ \ \ 2)2x {}^{2} + 4x = 0 \ \ 2x times (x + 2) = 0 \ \ x times (x + 2) = 0 \ \ x1 = 0 \ \ x + 2 = 0 \ \ x2 = - 2$

~•~•~•ZLOY_TIGROVSKIY~•~•~•

Answer 2

1)x2-x=0
x(x-1)=0
x= 0 x-1=0
x=1
2)2x2+4x=0
2x(x+2)=0
x=0 x+2=0
x= - 2