Question

Sin(3x + pi/3)=√2/2 Решите пожалуйста

Answer 1

(3х+π/3)=(-1)ⁿarcsin(√2/2)+πn; n∈

3х+π/3=(-1)ⁿπ/4+πn;  n∈Z

3х=(-1)ⁿπ/4-π/3+πn; n∈Z

х=(-1)ⁿπ/12-π/9+πn/3; n∈Z