Question

Разложите на множители 81b^4-16 и x^2-x-y^2-y

Answer 1

1)81b^4-16=(9b^2+4)(9b^2-4)=(9b^2+4)(3b+2)(3b-2)

2)x^2-x-y^2-y=x^2-y^2-x-y=(x+y)(x-y)-(x+y)=(x+y)(x-y-1)

Answer 2

cgc

Answer 3

спс