Question

Найдите среднее арифметическое чисел
1) 10,1; 9,4 и 9,9;

Answer 1

• $10.1 + 9.4 + 9.9 = 29.4 div 3 = 9.8$

$11 frac{1}{2} + 9.7 + 9 frac{4}{5} + 10.2 = 20 frac{5 + 8}{10} + 19.9 = 20 frac{13}{10} + 19.9 = 21.3 + 19.9 = 41.2 div 4 = 10.3$

• $frac{9}{20} + 0.65 + frac{2}{5} = frac{9 + 8}{20} + frac{65}{100} = frac{17}{20} + frac{13}{20} = frac{30}{20} = frac{3}{2} div 3 = frac{3}{2 times 3} = frac{1}{2} = 0.5$
• $5.9 + 6.1 + 6 + 4.8 = 22.8 div 4 = 5.7$
• $3.6 + 3 frac{3}{4} + 3.66 = 7.26 + 3.75 = 11.01 div 3 = 3.67$

$5.21 + 4.98 + 5.14 + 8.67 = 24 div 4 = 6$