Question

а)16у^2-0,25
б)а^2+10ав+25в^2

Answer 1

а)16у^2-0,25=(4у)^2-0,5^2=(4-0,5)(4+0,5)

б)а^2+10ав+25в^2=а^2+2×5ав+(5в)^2=(а+5в)^2