Question

Помогите, пожалуйста, решить уравнение

Answer 1

$frac{3y-2}{y-3}-frac{y-4}{y+3}+frac{15y-1}{(3-y)(3+y)}=0\\frac{3y-2}{y-3}-frac{y-4}{y+3}-frac{15y-1}{(y-3)(y+3)} =0\\frac{3y^{2}+9y-2y-6-y^{2}+4y+3y-12-15y+1}{(y-3)(y+3)}=0\\frac{2y^{2}-y-17 }{(y-3)(y+3)}=0\\left { {{2y^{2}-y-17=0 } atop {yneq-3;yneq3}} right.$

$2y^{2}-y-17=0\\D=(-1)^{2}-4*2*(-17)=1+136=137\\y_{1}=frac{1-sqrt{137}}{4}\\y_{2}=frac{1+sqrt{137} }{4} }$