Question

ПОМОГИТЕ ПОЖАЛУЙСТА!!!!!

Answer 1

$y = {x}^{2} sqrt{x} \ y' = ( {x}^{2} )' times sqrt{x} + {x}^{2} times ( sqrt{x} )' \ y' = 2x times sqrt{x} + {x}^{2} times frac{1}{2 sqrt{x} } \ \ y'(4) = 2 times 4 times sqrt{4} + {4}^{2} times frac{1}{2 times sqrt{4} } = \ = 16 + 16 times frac{1}{4} = 16 + 4 = 20$