Question

(4х-24)/(х-5)+(х-9)/(5-х)

Answer 1

$frac{4x-24}{x-5}+frac{x-9}{5-x}=frac{4x-24}{x-5}-frac{x-9}{x-5}=frac{4x-24-x+9}{x-5}= frac{3x-15}{x-5}=\\frac{3(x-5)}{x-5}=3$