Question

(2x-3)^2>25.

(2x+7)^2≤169 ​

Answer 1

1)$(2x-3)^{2} >25rightarrow left[begin{array}{cc}(2x-3)>5\(2x-3)<-5end] rightarrow left[begin{array}{cc}2x>8\2x<-2end] rightarrow left[begin{array}{cc}x>4\x<-1end]$

Ответ: $xin(-infty;-1)cup(4;+infty)$

2)$(2x+7)^{2}leq169rightarrow left[begin{array}{cc}(2x+7)leq13\(2x+7)geq-13end] rightarrowleft[begin{array}{cc}2xleq6\2xgeq-20end] rightarrowleft[begin{array}{cc}xleq3\xgeq-10end]$

Ответ:$xin[-10;3]$