Question

как решить уравнение (4x+3)-(10x+11)=7x(13-4x) и (2x+3)-(5x+11)=7x(13-2x)

Answer 1

(4х+3)-(10х+11)=7х(13-4х)
4х+3-10х-11=91-28х
4х-10х+28=91+11-3
22х=99
х=9922
х=4,5

(2х+3)-(5х+11)=7х(13-2х)
2х+3-5х-11=91-14х
2х-5х+14х=91+11-3
11х=99
х=9911
х=9