Question

(x-7)^2+3=(x-2)(x+2) помогите их срочно!​

Answer 1

$(x-7)^2+3=(x-2)(x+2) \ {x}^{2} - 14x + 49 + 3 = {x}^{2} - 4 \ {x}^{2} - {x}^{2} - 14x + 52 = - 4 \ - 14x = - 4 - 52 \ - 14x = - 56 \ x = frac{ - 56}{ - 14} \ x= 4$

ответ: 4