Question

Упростите выражение:

Answer 1

$sqrt[3]{b}:b^{-frac{1}{6} } =b^{frac{1}{3} }:b^{-frac{1}{6} }=b^{frac{1}{3}-(-frac{1}{6})}=b^{frac{2}{6}+frac{1}{6}}=b^{frac{3}{6}}=b^{frac{1}{2}}=sqrt{b}$