Question

Решите уравнение
√2sinx/3=-1

Answer 1

$sqrt2, sinfrac{x}{3}=-1\\sinfrac{x}{3}=-frac{1}{sqrt2}\\frac{x}{3}=(-1)^{n}cdot (-frac{pi}{4})+pi n; ,; nin Z\\x=(-1)^{n+1}cdot frac{3pi }{4}+3pi n; ,; nin Z$