Question

помогите пожалуйста решить)​

Answer 1

$begin{equation*} begin{cases}ttcfrac{y}{3}-cfrac{x}{2} =1 |cdot6\\ tt2^{x-2}cdot2^y=8 end{cases}end{equation*} Rightarrow begin{equation*} begin{cases}tt 2y-3x=6 \\ tt2^{x-2+y}=2^3 end{cases}end{equation*} Rightarrow begin{equation*} begin{cases}tt 2y-3x=6 \\ tt x-2+y=3 end{cases}end{equation*} Rightarrow$

$displaystylettRightarrowleft {{{2y-3x=6} atop {x=5-y }} right. Rightarrowleft {{{2y-3(5-y)=6} atop {x=5-y }} right. Rightarrowleft {{{2y-15+3y=6} atop {x=5-y }} right. Rightarrow\\\ Rightarrowleft {{{5y=21 } atop {x=5-y}} right. Rightarrowleft {{{y=4,2 } atop {x=5-y}} right. Rightarrowleft {{{y=4,2 } atop {x=0,8}} right.$

Ответ: (0,8; 4,2)