Question

#6 помогите. (lim)
Хотя бы 3 решите

Answer 1

$limlimits _{x to infty}(frac{7}{x^3}+frac{6}{x^2})=0+0=0\\limlimits _{x to infty} Big ((frac{1}{x^2}+2)cdot (frac{3}{x^3}-4)Big )=2cdot (-4)=-8\\limlimits _{x to infty}frac{1+2x}{3x-7}=limlimits _{x to infty}frac{frac{1}{x}+2}{3-frac{7}{x}}=frac{2}{3}\\limlimits _{x to infty}(x^2+x-2)=infty$