Question

Решите уравнение, пожалуйста!

Answer 1

Объяснение:

2sin(√x + π/2) = √3,

sin (√x + π/2 ) =√3 / 2,

√x + π/2 = (-1)ⁿ(π/3) + πn,  n∈Z

1)

√x + π/2 = (π/3) + 2πn,   

√x = (π/3 - π/2) + 2πn,

√x = (2π/6 - 3π/6) + 2πn,

√x = (-π/6) + 2πn    n = 1,2,3,....

x = π²(-1/6 + 2n )²    n=1,2,3,....

2)

√x + π/2 = π - (π/3) + 2πk,  

√x = π - π/2- (π/3) + 2πk,   

√x = π/6 + 2πk       k=1,2,3,....

x = π²(1/6 + 2k)²      k=1,2,3,...