Question

вычислить:
3√6tgacos(π - a), если sina = √6/5​

Answer 1

$3sqrt{6}tgalpha Cos(pi -alpha)=3sqrt{6} tgalpha*(-Cosalpha)=-3sqrt{6}*frac{Sinalpha }{Cosalpha}*Cosalpha=-3sqrt{6}Sinalpha=-3sqrt{6}*frac{sqrt{6} }{5}=- frac{18}{5}=-3,6$