Question

Помогите сделать три номера по алгебре, даю 54 балла. Спасибо

Answer 1

#1.

▪а)

$16 times {( - 8)}^{ - 1} = 16 times ( - frac{1}{8} ) = - 2$

▪б)

${2}^{ - 3} - {( - 2)}^{ - 4} = frac{1}{8} - frac{1}{16} = frac{2 - 1}{16} = frac{1}{16}$

▪в)

$- {3}^{0} times {( frac{2}{3}) }^{ - 1} + {(0.5)}^{ - 2} = - 1 times frac{3}{2} + 4 = - 1.5 + 4 = 2.5$

▪г)

${( frac{1}{5} - frac{1}{25}) }^{ - 1} div {(3.2)}^{ - 2} = {( frac{5 - 1}{25}) }^{ - 1} div {( frac{32}{10}) }^{ - 2} = frac{25}{4} div {( frac{16}{5}) }^{ - 2} = frac{25}{4} div frac{25}{ {4}^{4} } = frac{25 times {4}^{4} }{4 times 25} = {4}^{3} = 64$

#3.

▪а)

${a}^{ - 1} {b}^{ - 2} - {a}^{ - 2} {b}^{ - 1} = frac{1}{a {b}^{2} } - frac{1}{ {a}^{2} b} = frac{a - b}{ {a}^{2} {b}^{2} }$

▪б)

$( {xy}^{ - 1} - {x}^{ - 1} y) {(x - y)}^{ - 1} = ( frac{x}{y} - frac{y}{x} ) times frac{1}{x - y} = frac{ {x}^{2} - {y}^{2} }{xy} times frac{1}{x - y} = frac{(x - y)(x + y)}{xy(x - y)} = frac{x + y}{xy}$