Question

Найдите производную сложной функции

Answer 1

$y=frac{4}{(12x-1)^3};f(a)=f^3(12x-1)=f^3(a)\y'=(frac{4}{f^3(a)})'=(4*f^{-3}(a))'=4*(-3)*f^{-3-1}(a)*(a)'=-12*f^{-4}(a)*(a)';\y'=frac{-12}{(12x-1)^4}*(12x-1)'= frac{-12*12}{(12x-1)^2}=frac{-144}{(12x-1)^4}$