Question

разложите на множители y^2-2y-24 и 64y^4+1

Answer 1

1)
$y^{2} -2y-24= y^{2} -6y+4y-24=y(y-6)+4(y-6)=\ (y+4)(y-6)$
2)
$64 y^{4}+1=64y ^{4} +16 y^{2} -16 y^{2}+1=(8y ^{2} +1) ^{2} -16 y^{2} =\ (8y ^{2}+1) ^{2} -4 ^{2} y^{2} =(8y ^{2} +1-4y)(8 y^{2}+1+4y)$