Question

упростите выражение 4(c-3)^2(c+3)^2-3(c+4)(4-c)^2

Answer 1

$4(c-3)^2(c+3)^2-3(c+4)(4-c)^2 =\\4[(c-3)(c+3)]^2-3(c+4)(4-c) (4-c)=\\4(c^2-9)^2-3(16-c^2) (4-c)=\\4(c^4-18c^2+81)-3(64-16c-4c^2+c^3)=\\4c^4-72c^2+324-192+48c+12c^2-3c^3=\\4c^4 - 3c^3 - 60c^2 + 48c + 132$