Question

Сократите дробь: а) 12р6к²/8р⁴к5
Б) 6х+6у/х²-у²

Answer 1

$1)~displaystylettfrac{12p^6k^2}{8p^4k^5}=frac{3p^2}{2k^3};\\\2)~frac{6x+6y}{x^2-y^2}=frac{6(x+y)}{(x-y)cdot(x+y)}=frac{6}{x-y}$