Question

Решите систему уравнений
2√x+y -3√x-y =3
3√x+y +√x-y =10

Answer 1

Ответ:

$(x;y)=(5;4)$

Объяснение:

$left { {{2sqrt{x+y} -3sqrt{x-y} =3} atop {3sqrt{x+y} +sqrt{x-y} =10}} right. <=>left { {{2sqrt{x+y} -3sqrt{x-y} =3} atop {9sqrt{x+y} +3sqrt{x-y} =30}} right.=>11sqrt{x+y}=33<=>\<=>sqrt{x+y}=3<=>x+y=9=>2* sqrt{9} -3sqrt{x-y}=3<=>\<=>sqrt{x-y}=1<=>x-y=1\left { {{x+y=9} atop {x-y=1}} right.  =>(x;y)=(5;4)$