Question

Решите уравнение: а)(31+а) : 0,9 = 216,4; б)(0,59+9/10×х) × 100 = 959​

Answer 1

$a)\\left[begin{array}{ccc}(31+a):0,9=216,4\31+a=216.4*0.9\31+a=194.76\a=194.76-31\a=163.76end{array}right]$

$b)\\left[begin{array}{ccc}(0.59+0.9x)*100=959\0.59+0.9x=959:100\0.59+0.9x=9.59\0.9x=9.59-0.59\0.9x=9\x=10end{array}right]$