Question

СРОЧНО 2.1 ДАЮ 15 БАЛЛОВ !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$frac{12-x}{x^{2}+6x }+frac{3}{x^{2}-6x }=frac{6}{x^{2}-36 }\\frac{12-x}{x(x+6)}+frac{3}{x(x-6)}-frac{6}{(x+6)(x-6)}=0\\frac{12x-72-x^{2}+6x+3x+18-6x }{x(x+6)(x-6)}=0\\frac{-x^{2}+15x-54 }{x(x+6)(x-6)} =0\\frac{x^{2}-15x+54 }{x(x+6)(x-6)}=0\\left { {{x^{2}-15x+54=0 } atop {xneq0;xneq-6;xneq6}} right. \\x_{1} =9\\x_{2}=6$

x = 6 - посторонний корень

Ответ : 9